3.15 \(\int x^3 \log ^3(c x) \, dx\)

Optimal. Leaf size=45 \[ \frac {1}{4} x^4 \log ^3(c x)-\frac {3}{16} x^4 \log ^2(c x)+\frac {3}{32} x^4 \log (c x)-\frac {3 x^4}{128} \]

[Out]

-3/128*x^4+3/32*x^4*ln(c*x)-3/16*x^4*ln(c*x)^2+1/4*x^4*ln(c*x)^3

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Rubi [A]  time = 0.04, antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2305, 2304} \[ \frac {1}{4} x^4 \log ^3(c x)-\frac {3}{16} x^4 \log ^2(c x)+\frac {3}{32} x^4 \log (c x)-\frac {3 x^4}{128} \]

Antiderivative was successfully verified.

[In]

Int[x^3*Log[c*x]^3,x]

[Out]

(-3*x^4)/128 + (3*x^4*Log[c*x])/32 - (3*x^4*Log[c*x]^2)/16 + (x^4*Log[c*x]^3)/4

Rule 2304

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[((d*x)^(m + 1)*(a + b*Log[c*x^
n]))/(d*(m + 1)), x] - Simp[(b*n*(d*x)^(m + 1))/(d*(m + 1)^2), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[m, -1
]

Rule 2305

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[((d*x)^(m + 1)*(a + b*Lo
g[c*x^n])^p)/(d*(m + 1)), x] - Dist[(b*n*p)/(m + 1), Int[(d*x)^m*(a + b*Log[c*x^n])^(p - 1), x], x] /; FreeQ[{
a, b, c, d, m, n}, x] && NeQ[m, -1] && GtQ[p, 0]

Rubi steps

\begin {align*} \int x^3 \log ^3(c x) \, dx &=\frac {1}{4} x^4 \log ^3(c x)-\frac {3}{4} \int x^3 \log ^2(c x) \, dx\\ &=-\frac {3}{16} x^4 \log ^2(c x)+\frac {1}{4} x^4 \log ^3(c x)+\frac {3}{8} \int x^3 \log (c x) \, dx\\ &=-\frac {3 x^4}{128}+\frac {3}{32} x^4 \log (c x)-\frac {3}{16} x^4 \log ^2(c x)+\frac {1}{4} x^4 \log ^3(c x)\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 45, normalized size = 1.00 \[ \frac {1}{4} x^4 \log ^3(c x)-\frac {3}{16} x^4 \log ^2(c x)+\frac {3}{32} x^4 \log (c x)-\frac {3 x^4}{128} \]

Antiderivative was successfully verified.

[In]

Integrate[x^3*Log[c*x]^3,x]

[Out]

(-3*x^4)/128 + (3*x^4*Log[c*x])/32 - (3*x^4*Log[c*x]^2)/16 + (x^4*Log[c*x]^3)/4

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fricas [A]  time = 0.42, size = 37, normalized size = 0.82 \[ \frac {1}{4} \, x^{4} \log \left (c x\right )^{3} - \frac {3}{16} \, x^{4} \log \left (c x\right )^{2} + \frac {3}{32} \, x^{4} \log \left (c x\right ) - \frac {3}{128} \, x^{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*log(c*x)^3,x, algorithm="fricas")

[Out]

1/4*x^4*log(c*x)^3 - 3/16*x^4*log(c*x)^2 + 3/32*x^4*log(c*x) - 3/128*x^4

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giac [A]  time = 0.21, size = 37, normalized size = 0.82 \[ \frac {1}{4} \, x^{4} \log \left (c x\right )^{3} - \frac {3}{16} \, x^{4} \log \left (c x\right )^{2} + \frac {3}{32} \, x^{4} \log \left (c x\right ) - \frac {3}{128} \, x^{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*log(c*x)^3,x, algorithm="giac")

[Out]

1/4*x^4*log(c*x)^3 - 3/16*x^4*log(c*x)^2 + 3/32*x^4*log(c*x) - 3/128*x^4

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maple [A]  time = 0.03, size = 38, normalized size = 0.84 \[ \frac {x^{4} \ln \left (c x \right )^{3}}{4}-\frac {3 x^{4} \ln \left (c x \right )^{2}}{16}+\frac {3 x^{4} \ln \left (c x \right )}{32}-\frac {3 x^{4}}{128} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*ln(c*x)^3,x)

[Out]

-3/128*x^4+3/32*x^4*ln(c*x)-3/16*x^4*ln(c*x)^2+1/4*x^4*ln(c*x)^3

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maxima [A]  time = 0.54, size = 29, normalized size = 0.64 \[ \frac {1}{128} \, {\left (32 \, \log \left (c x\right )^{3} - 24 \, \log \left (c x\right )^{2} + 12 \, \log \left (c x\right ) - 3\right )} x^{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*log(c*x)^3,x, algorithm="maxima")

[Out]

1/128*(32*log(c*x)^3 - 24*log(c*x)^2 + 12*log(c*x) - 3)*x^4

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mupad [B]  time = 3.29, size = 29, normalized size = 0.64 \[ \frac {x^4\,\left (32\,{\ln \left (c\,x\right )}^3-24\,{\ln \left (c\,x\right )}^2+12\,\ln \left (c\,x\right )-3\right )}{128} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*log(c*x)^3,x)

[Out]

(x^4*(12*log(c*x) - 24*log(c*x)^2 + 32*log(c*x)^3 - 3))/128

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sympy [A]  time = 0.13, size = 42, normalized size = 0.93 \[ \frac {x^{4} \log {\left (c x \right )}^{3}}{4} - \frac {3 x^{4} \log {\left (c x \right )}^{2}}{16} + \frac {3 x^{4} \log {\left (c x \right )}}{32} - \frac {3 x^{4}}{128} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*ln(c*x)**3,x)

[Out]

x**4*log(c*x)**3/4 - 3*x**4*log(c*x)**2/16 + 3*x**4*log(c*x)/32 - 3*x**4/128

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